Question

so i have a question, how do i write the standard form of this equation of a line that is paralell to the given line? 2x-y+6=0 , (0,4)

Answer 1

the given line can be written y = 2x + 6 which is the slope / intercept form
the slope is coefficient of x = 2
the line parallel must also have slope 2
it must also pass thru point (0,4).
using the standard form
y-y1 = m(x-x1) where m is slope and x1 = 0 y1 = 4

y-4 = 2(x-0)
y - 4 = 2x
y - 2x - 4 = 0

Answer 2

remove the constant and calibrate with the given point for a new constant; the rest of it stays the same

Answer 3

while jimmys is fine; some frown upon not haveing the x first and it being negative if it is

Answer 4

2x -y +4 = 0

Answer 5

thank you all for all he help i might be posting some more on here before the night is over