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Mathematics 21 Online
OpenStudy (anonymous):

http://www.cpm.org/students/homework/A2C_Problems/A2C_Ch2_Answers/A2C2.1.1/A2C_2_14.html can someone please explain how to do this?

OpenStudy (anonymous):

doesn't load for me

OpenStudy (anonymous):

it usually takes a few seconds,?

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

at least the first one. idont understand how to do it.

OpenStudy (anonymous):

If you have the same base (in the first one they are both 5), you just subtract the exponents. So you should get \[5^{723}/5^{721}=5^{723-721}=5^2=25\]

OpenStudy (anonymous):

try the next one and let me know what you get

OpenStudy (anonymous):

you subtract the exponets....soo...i got 3^51 (: but for C. i dont get why th four on thebotton isnt there for the final answe?

OpenStudy (anonymous):

agreed

OpenStudy (anonymous):

hmm, oh well. maybe just a typo.. thank you so much! :D

OpenStudy (anonymous):

So you just have a constant (3/7) multiplied by 4^1001/4^997=4^4

OpenStudy (anonymous):

sorry for the typo above

OpenStudy (anonymous):

you good on the last one?

OpenStudy (anonymous):

last one was simple:)

OpenStudy (anonymous):

Its C im having trouble on still...sorry ):

OpenStudy (anonymous):

We have \[(\frac{3}{7})(\frac{4^{1001}}{4^{997}})=(\frac{3}{7})(4^4)=\frac{3*4^4}{7}\]

OpenStudy (anonymous):

OHHHHHHHHHHHHHHHH!!!!

OpenStudy (anonymous):

LOL...yeah they look like 3.4 and 7.4 instead of 3*4 and 7*4 on my browser lol

OpenStudy (anonymous):

HAHAAH yes! i totallyget it now. my bad :)

OpenStudy (anonymous):

hehe

OpenStudy (anonymous):

gotta bathe my little ones...good luck on the rest :))

OpenStudy (anonymous):

:) thank you so much!!!

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