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Prove that this equation is an identity: {cosine(alpha)-sine(alpha)}^2=1-2 sine(alpha)cosine(alpha)
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\[(cosx - sina)^2 = cos^2x + sin^2x - 2*sinx*cosx\]
you DIDN'T ANSWER THE QUESTION!!!!!
I did !!!
no.... you just restated it and added more....
\[sin^2x + cos^2x = 1 \]
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\[\text{^ ^ Now try to do on your own}\]
i did... i kinda got it not really
\[(\cos(x)-\sin(x))^2=\cos^2(x)+\sin^2(x)-2\cos(x)\sin(x)=1-2\cos(x)\sin(x)\] but ishaan already stated this
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