Find the inverse of f(x)=(1+3x)/(5-2x) Please show work!
All you gotta do is switch the x and y and solve bro
solve for x becuase f(x) would be y
you want the steps?
yeah, but would you solve for y? I got up to this: \[(5-2y)x=1+3y\]
ok
\[(5-2y)x=1+3y\] \[5x-2xy=1+3y\] \[5x-1=3y-2xy\] \[5x-1=(3-2x)y\] \[\frac{5x-1}{3-2x}=y\]
i just did this problem a few posts back, but i don't know how to retrieve it
think of the inverse like the opposite...that's why you have to switch them. If you can, graph it and you'll be able to see it a lot easier.
so \[f^{-1}(x)=\frac{5x-1}{3-2x}\] assuming i did the algebra right. it was the steps you wanted yes?
@Mandolino, I deleted the question because I awarded you a medal but I still needed help. Sorry.
@satellite73 Thanks!
i think there is a sign error, if you move -2xy to the rhs then is should be positive. i got earlier (hope its right)\[y=\frac{5x-3}{2x+3}\]
i think there is a sign error, if you move -2xy to the rhs then is should be positive. i got earlier (hope its right)\[y=\frac{5x-3}{2x+3}\]
should be 5x-1 in the numerator
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