Question

how do you make and equation with absoulte value numberline?? Help!

Answer 1

are you asking how to graph an equation that involves absolute value, or what?

Answer 2

how to make an equation from a graph

Answer 3

let's say the equation is of the form y = |x + a| + b. The point of the "v" is at (-a,b). If the "v" is upside down, throw a negative sign in front of the absolute value.

Answer 4

for example, go here and play with a and b: http://bit.ly/pGAgwH

Answer 5

if the points are 1 and 11 then what would the equation look like
If my paper says write an equation for the absoulute value for each graph and the graph is just a numberline with 2 points on it like -6 and -2 what am I suppose to do

Answer 6

absolute value of -6 is 6. put a dot on the 6. similarly for -2.

Answer 7

what you're describing doesn't sound like an equation.

Answer 8

I have the dots but I don't know how to write an equation using those 2 numbers

Answer 9

you mean like |-6| = 6?

Answer 10

ok on another problem I had l3t+6l=9 and i figured out the 2 points for the solution set were -5 and 1. But now I have the 2 points and don't know how to write and equation

Answer 11

ooooooooooh. if the points are -2 and -6, the equation could be |t + 4| = 2, or any multiple of that, like |2t + 8| = 4

Answer 12

you know the point of the v in the absolute value graph has to be halfway between the two solutions. So you average them and then the inside of your absolute value is
|t - TheAverageYouJustGot|

Then the right hand side of the equals sign is the distance between the two points, divided by 2. So for 1 and 11, you get |t - 6| = 5

Answer 13

That's supposed to be "TheAverageYouJustGot"

Answer 14

"The Average You Just Got" weird. it changes it if you type it without spaces!

Answer 15

ok im going to try the next one and then i'll ask if its right

Answer 16

ok, this probably is wrong but i'm trying- if the 2 numbers are -7 and 1 could my equation be lt-6l=4?

Answer 17

close! but the average of -7 and 1 is -3...

Answer 18

so the inside of the absolute value is |t + 3|