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Mathematics 21 Online
OpenStudy (anonymous):

A constant force moves an object along a straight line from point (0, -2, 9) to point (-10, 3, -1). Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.

OpenStudy (anonymous):

Distance formula for two points in 3 dimensions\[d=\sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}+(z_1-z_2)^{2}}\] Work is force times distance. We know the distance, but the force is not given...?

OpenStudy (anonymous):

constant force 3i+1j-2k

OpenStudy (anonymous):

d=15 right?

OpenStudy (anonymous):

I got 28.7

OpenStudy (anonymous):

its wrong

OpenStudy (anonymous):

Yeah you're right I was taking 25^2 instead of 5^2

OpenStudy (anonymous):

Multiply by the magnitude of the force.

OpenStudy (anonymous):

how do i get the magnitude of the force?

OpenStudy (anonymous):

Pythag theorem

OpenStudy (anonymous):

ok so the distance is 15 right? i multiply 15 X what?

OpenStudy (anonymous):

\[\sqrt{3^{2}+1^{2}+2^{2}}\]

OpenStudy (anonymous):

i did that and my answer is wrong

OpenStudy (anonymous):

\[15 X \sqrt{14}\] =56.125

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