Question

Solve. x2 – 4x – 6 = 0

Answer 1

is it x sqr?

Answer 2

dhashni where r u from?

Answer 3

me!!!! i am from india

Answer 4

solve using quadratic formula

\[(x = -b \pm \sqrt{b^2 - 4ac})/2a\]

Answer 5

yes it is, do u want me to draw it for u

Answer 6

one correction please

it is
x = ................ /2a

Answer 7

x = 2+/-sqrt(10)

Answer 8

x = 5.16, -1.16

Answer 9

it isnt that simple, i wish it were there are 4 answers given and none of them are what is given here

Answer 10

kush write your qus

Answer 11

so what are the options?

Answer 12

when you want to show x or any number to the power of some number use =
x^2 = \[x^2\]

Answer 13

x = 2+/-sqrt(10)
the only thing is it isnt a negative sqrt it is a positive sqrt

Answer 14

Possible intermediate steps:
x^2-4 x-6 = 0
Add 6 to both sides:
x^2-4 x = 6
Add 4 to both sides:
x^2-4 x+4 = 10
Factor the left hand side:
(x-2)^2 = 10
Take the square root of both sides:
abs(x-2) = sqrt(10)
Eliminate the absolute value:
x-2 = -sqrt(10) or x-2 = sqrt(10)
Add 2 to both sides:
x = 2-sqrt(10) or x-2 = sqrt(10)
Add 2 to both sides:
x = 2-sqrt(10) or x = 2+sqrt(10)

Answer 15

my answers are correct, just not written in the same way. it depends, if you are allowed to use a scientific calculator, or not.

Answer 16

\[x = 2 -\sqrt{10} \]
\[x = \sqrt{10 + 2} \]

Answer 17

The above are correct. What answers do they give you?

Answer 18

\[ x \approx -1.1622776601684 \]
\[ x \approx 5.1622776601684 \]

Answer 19

\[x=(-b \pm \sqrt{b ^{2}-4ac})/2a\]

a=1, b=-4 c=-6

x= \[(-(-4) +\sqrt{(-4)^{2}-4(1)(-6) )}/((2)(1))\] =\[2+\sqrt{5}\]
or
x= \[(-(-4) -\sqrt{(-4)^{2}-4(1)(-6) )}/((2)(1))\] =\[2-\sqrt{5}\]