What constant rate would be required to change the volume from the observed value at t=1.5 to the one at t=3? we call this average rate of change on the interval similar to the way average velocity is defined in this section).
t= 0 .5 1 1.5 2 2.5 3
v=5 5.2 4.8 1.7 2.9 4.1 5

Question

What constant rate would be required to change the volume from the observed value at t=1.5 to the one at t=3? we call this average rate of change on the interval similar to the way average velocity is defined in this section).
t= 0   .5   1    1.5  2    2.5  3
v=5  5.2 4.8  1.7  2.9  4.1  5

amistre64 · Answer

its the slope of the points (1.5,1.7) and (3,5)

amistre64 · Answer

y' = c

y = cx + C

amistre64 · Answer

find the equation to the line between the 2 points is about the best i can give you on it

anonymous · Answer

5-1.7/3-1.5?

anonymous · Answer

yea i cant find it. i keep getting different outcomes for each equation

anonymous · Answer

myininaya? could you help me?

amistre64 · Answer

(3.0,5.0)
-(1.5,1.7)
-----------
  1.5, 3.3; slope = 33/15

amistre64 · Answer

or 11/5 if your lucky lol

amistre64 · Answer

y = mx -mPx + Py

y = (11/5)x - 11(3)/5 + 5

y = (11/5)x -33/5 + 25/5

y = (11/5)x - 8/5  is what i get if its right

anonymous · Answer

but how does that get you the constant rate needed?

amistre64 · Answer

"we call this average rate of change"

the average rate of change is simply the slope of the line betweem the extremes on an interval

amistre64 · Answer

your interval is from 1.5 to 3

amistre64 · Answer

i believe the constant rate of change needed; would be just the slope itself

anonymous · Answer

ah yess 2.2 thank you!

amistre64 · Answer

|dw:1315925437770:dw|

anonymous · Answer

could you help me with another rate of change?