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Mathematics 10 Online
OpenStudy (anonymous):

(I know this is more chemistry oriented, but I was hoping someone would still be able to help me out) Water has a density of 0.997 g/cm^3 at 25 degrees C; ice has a density of 0.917 g/cm^3 at -10 degrees C. (question part a) If a soft drink bottle whose volume is 1.50L is completely filled with water and then frozen to -10 degrees C, what volume does the ice occupy? (question part b) Can the ice be contained within the bottle?

OpenStudy (anonymous):

since 1 cm^3=1ml 1.50L(1000mL/1L)(0.997g/mL)(cm^3/0.917g)(1ml/1cm^3)(1L/1000mL)=

OpenStudy (anonymous):

1.63|08 L

OpenStudy (anonymous):

this makes sense because when water turns to ice the bonds get slightly largers creating more space, so no the volume is too small to contain the frozen water

OpenStudy (anonymous):

got it. thanks!!

OpenStudy (anonymous):

chemistry major :)

OpenStudy (anonymous):

well density is the mass per unit volume and so the the volume is inversely proportional to the density. So right off the bat the ice can not be contained if the bottle is filled to the top with water (think of placing a soda can in the freezer, bad idea). The change in volume will be 1500cm^3*.917 g/cm^3 (this will give you the mass of water contained in the bottle. Now that you know the mass you can divide that mass by the density at the lower temperature giving you the volume at -10.

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