Question

im (x+1)^7(2x)^2
x->2

i found the answer to this and its asking now what laws did i use? quotient, power, product, difference, root, constant mult, and sum?

Answer 1

does x=2 make it go bad?

Answer 2

as far as the laws go, i got no idea what you did, or even which ones apply :)

Answer 3

no the lim is 17496
i just dont know the rules i used to get that lol

Answer 4

im sure you added, multiploed and powered

Answer 5

lol me too but its not taking that as an answer

Answer 6

how did you get that

Answer 7

i just plugged in 2 and got the answer lol

Answer 8

\[\lim_{x \rightarrow 2}(x+1)^7(2x)^2=(2+1)^7(2(2))^2=(3)^74^2=2187(16)=34992\]

Answer 9

thats what you get pluggin in 2

Answer 10

Plug in the the limit that x is approaching and solve like normal

Answer 11

oh ya your right sorry i typed it in wrong. it was supposto be 2x^2. so you would do 2187*8

Answer 12

yes now you get what you got

Answer 13

\[\lim_{x \rightarrow 2}[(x+1)^72x^2]=\lim_{x \rightarrow 2}(x+1)^7 \cdot \lim_{x \rightarrow 2}(2x^2)\]
\[=(\lim_{x \rightarrow 2}(x+1))^7 \cdot 2 \lim_{x \rightarrow 2}x^2\]
\[=(2+1)^7 \cdot 2 \cdot (2)^2\]

Answer 14

product used in first step
power and constant used in second step

Answer 15

and i guess you could put another step inside the parentheses and used the sum limit rule

Answer 16

why dont you just say its a continuous function defined over all x and thus the limit is equal to the function value

Answer 17

he said he wanted limit properties to be used