how to factor -x^2 - 2x + 15
First divide everything by -1.
You get x^2+2x-15
It factors then as (x+5)(x-3) and you're done.
(-x-5)(x-3)
(-x-5)(x-3)
No, you need to factor a (-1) out of your (-x-5) term. Your leading term cannot be negative.
Well, then you'd better include it in your final answer (-1)(x+5)(x-3).
No, because you can't factor originally with a negative x^2.
So that factoring is wrong.
-(x+5)(x-3)
-(x+5)(x-3) this is the right answer i think but how
Well you can begin like OakTree and pull out the -1: -(x^2+2x-15); then you are looking for something like (x+a)(x+b) but what are a and b? Consider what that looks like when multiplied out: x^2+ax+bx+ab. The x^2 is right. ax+bx has to equal 2x; therefor a+b=2 ab must equal -15 So consider the factor pairs of -15 that could be a and b: 1,-15; -1,15; 3,-5; -3,5 Only the last pair adds to 2, so it must be -(x-3)(x+5)
thanks
-x^2 - 2x + 15 = -(x^2+2x-15) = - (x-5)(x+3)
no, both x's would be negative
no negative outside
it's ok to have negative outside too, both ways work.
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