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evaluate the integral ∫xsin x/2 dx
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parts?
yeah integrate by parts. \[\int fdg=fg-\int gdf\] use \[f=x\] \[df=1\] \[dg=\sin(\frac{x}{2})\] \[g=-2\cos(\frac{x}{2})\] and you get it in one step basically \[-2x\cos(x)+2\int\cos(\frac{x}{2})dx\]
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