Question

Find all values of x at which the tangent
line to the graph of
y =x^2/(x + 3)
is horizontal.

Answer 1

are you in Calculus?

Answer 2

Yes

Answer 3

The tangent graph is horizontal when the derivative = 0.
\[y' = ((x+3(2x)) - x ^{2})/ ((x+3)^{2})\]
x = 0,7

Answer 4

using the Quotient Rule you can find the derivative.
(x+3)(2x) - (x^2)(1) "over" (x+3)^2
(2x^2+6x) - (x^2) "over" (x+3)^2
(x^2+6x) "over" (x+3)^2
set = 0 and solve.

Answer 5

the answer choices dont have 7 in it

Answer 6

dammit... out of your thing i got -3, and 0. but it's not that. It's either 1. x = −3
2. x = −6
3. x = −3 , 0
4. x = −6 , 0
5. x = 5 , 0
6. x = 0
7. x = 5
but 3 and 6 are wrong

Answer 7

-.-