Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.600 pint of room-temperature water, how many kilojoules of heat energy will have been absorbed by the water at the moment it begins to boil?

Question

anonymous · Answer

36400 cal to heat 1 pint
0.6 pints (personally I think that's not enough -  he's clearly not eating well)
21840 cal
1 cal = 4.184 J (or whatever rate you use)
91378.56J = 91.37856kJ

Round to whatever level you need to.

anonymous · Answer

The density of liquid oxygen at its boiling point is 1.14  , and its heat of vaporization is 213  .
How much energy in joules would be absorbed by 3.0  of liquid oxygen as it vaporized?

anonymous · Answer

Can you help me with this problem

anonymous · Answer

I did it got 728.46 but that was wrong -_-