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HELP!!! 2x + 1 = RADICAL (3x^2 + 5x = 3)
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spamming not cool
not spamming - need help!
\[2x+1=\sqrt{3x^2+5x}=3\] This is what your problem looks like to me , but I do not think this is right
not quite the last term should be +3 under the radical sign - thanks for the clarification!
I got x= -1 and x = 2, but which one works? and am I close at all?
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Well to see which one works you would just plug those back in.
so I get x = 5 correct?
Yes that is correct because it works for both sides.
x=2 worked for me!
The x=2 is what I meant worked, so yes you did great. Looks like you knew how to do this all along. :)
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