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i believe you mean pi and not pie -sin(a)=-cos(pi/2-a) or sin(-a)=cos(pi/2+a) so we have cos(2a)=cos(pi/2+a) \[2a=\frac{\pi}{2}+a =>a=\frac{\pi}{2}\] so that is one value that works
there is another way to go about it
i see three intersections in my calculator all i can get is just pi/2 so let me think of another way
sin(a)=1 when a=pi/2 sin(a)=-1/2 when a=7pi/6 or 11pi/6
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three values! :)
very cool!
:)
@myininaya plz help http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e7147e60b8bbc8fb32c09c6
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