Find a unit vector orthogonal to −5 I + 2 J + 10 K and 0 I + 1 J + 0 K:
??? I + ??? J + ??? K
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OpenStudy (anonymous):
Use cross product.
OpenStudy (anonymous):
didnt work
OpenStudy (anonymous):
sure it does, [-10, 0, -5] is the answer.
OpenStudy (anonymous):
i j k
-5 2 10
0 1 0
=-10i+0j-5k which is what YTheManifold stated
OpenStudy (anonymous):
i did it but only the 0j is right
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OpenStudy (anonymous):
check the answer by calculating the scalar product to see if it is orthogonal
OpenStudy (anonymous):
what difference does that makes !?
OpenStudy (anonymous):
or you could DOT them which will be=0
a*b/||a||||b||=cos(x)
0=cos(x)
cos^-1(0)=x
x=pi/2 or (-3pi/2) which is orthogonal and if the cos^-1(x)=1 or -1 then they are parallel
OpenStudy (anonymous):
its not parallel i know that too !
OpenStudy (anonymous):
plus i don't need those properties
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OpenStudy (anonymous):
the unit vector is -10i+0j-5k/sqrt(100+25)
thats a unit vector does that look better?
5sqrt(5)
-2/sqrt(5)i+0j+-1/sqrt(5)k