find the area of the region that lies inside both curves of r=1+cost & r=1-cost
can you show me the work by integral plz
its not a line lol its circles
and i found the limits for t from pi/2 to 3pi/2
equal both equation: 1+cost=1-cost cost=0
AREA ?
I KNO THE T VALUES.. Pi/2 aand 3pi/2
lol i wasnt talking to you sory :)) and thanks for your help
for example: \[\Pi/2 \to 3\pi/2\] Then integra it \[\int\limits_{\pi/2}^{3\Pi/2}1+cost -(1-cost)dt\]
Manuelg your work is not correct, please don't post wrong results delibaretely. That confuses people.
why is wrong? You are wrong . I'm a theoretical physicist.
thanks alott ( I wasnt just sure about subtraction or adding btw the areas
since it says inside both
dont you get negative answer ???
the boundary is wrong. You must use : \[-\pi/2 \rightarrow \Pi/2\]
Area always is positive
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