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OpenStudy (anonymous):
find the area of the region that lies inside both curves of r=1+cost & r=1-cost
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OpenStudy (anonymous):
can you show me the work by integral plz
OpenStudy (anonymous):
its not a line lol its circles
OpenStudy (anonymous):
and i found the limits for t from pi/2 to 3pi/2
OpenStudy (anonymous):
equal both equation:
1+cost=1-cost
cost=0
OpenStudy (anonymous):
AREA ?
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OpenStudy (anonymous):
I KNO THE T VALUES.. Pi/2 aand 3pi/2
OpenStudy (anonymous):
lol i wasnt talking to you sory :)) and thanks for your help
OpenStudy (anonymous):
for example:
\[\Pi/2 \to 3\pi/2\]
Then integra it
\[\int\limits_{\pi/2}^{3\Pi/2}1+cost -(1-cost)dt\]
OpenStudy (anonymous):
Manuelg your work is not correct, please don't post wrong results delibaretely. That confuses people.
OpenStudy (anonymous):
why is wrong? You are wrong . I'm a theoretical physicist.
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OpenStudy (anonymous):
thanks alott ( I wasnt just sure about subtraction or adding btw the areas
OpenStudy (anonymous):
since it says inside both
OpenStudy (anonymous):
dont you get negative answer ???
OpenStudy (anonymous):
the boundary is wrong. You must use :
\[-\pi/2 \rightarrow \Pi/2\]
OpenStudy (anonymous):
Area always is positive
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