Question

The equation for a toy car is given by x(t)=.5t-3.5. Find the position at 4 seconds. At what instant is the position zero for x(t) =.5t-3.5 and for x-4. Also, how long will it take for the position to reach 12 meters.

Answer 1

I am really looking for someone to guide me through this. If you just want to give me the answer that's fine, but I would much rather know how to do this one.

Answer 2

You can just insert the time in to find position at 4s;
x(4)=.5(4)-3.5=-1.5

Answer 3

That is what I did with that. Exactly Answer was -1.5

Answer 4

To find the zero position you set the equation equal to 0 and solve for t
0=.5(t)-3.5
3.5=.5t
7=t

Answer 5

The position that equation becomes zero I calculated to be 7. The original Equation that is.

Answer 6

Now, if I calcualte that if t=4 do I just plug zerio in for x?

Answer 7

Is the original question supposed to say "x=4"?
or t=4

Answer 8

or just graph the sucker and look, lol

Answer 9

t=4 with the original equation being the about x(t)=.5t-3.5

Answer 10

wants me to calculate the position if t=4 at position zero (i am guessing position =x

Answer 11

thanks for taking the time to help me too, this is a long question, so I really appreciate it mcgyver

Answer 12

yes you can just plug it in for t; for the 12m part you have to insert for x and solve for t although graphing works too.
...my pleasure!

Answer 13

Lots of help man. I might have another in a second so if your still around take a look! Thanks so much!

Answer 14

Really, these are the same graph/line? The only thing different are the values I am looking at?

Answer 15

I could literally plot a table and find all my answers onthe graph?