For those who thought they knew their vectors:
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im goona invent the round vector :)
An airplane heads northeast at an airspeed of 700 km/hr, but there is a wind blowing from the west at 60 km/hr. In what direction does the plane end up flying? What is its speed relative to the ground?
No bonus points for answering before I post the question
btw look up quaternions if you want a round vector
wha???
northeast 700 km/hr wind west at 60 km/hr. |dw:1316125237813:dw|
nice, it just cuts off the page there .. lovely :/
your gonna have to shrink your screen to se that
noreaster is 45* <1,1> is good fer it and 60 west is just <0,1>
but magnitude counts
I don't know if that's correct; that's what I had thought but then I realized airspeed is the speed relative to the air. So, the 700 km/hr to the northeast may already have the wind built in?
nah, its a math model, not real life
70,6 35,3 is about as ratioed as i can get them
Okay I concede on the first part. But how do you get the ground speed?
20<35,35> 20< 0 , 3> ------------ 20<35,38>
measure the distance flown in one hour along the new path
or simply assume that these vectors are a one hour snapshot and put |a+b| as the answer
but .... 700 aint it, is it :) 700 ratios to sqrt(2), not a side
ya
same concept, but better mathical skills ;)
But by your reasoning the ground speed should just be 700 km/hr. Either the wind is factored in the airspeed, the angle is 45, and the ground speed is different or vice versa
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