A graphic designer and her assistant working together can complete an advertising layout in 6 days. The assistant working alone could complete the job in 16 more days than the designer working alone. How long would it take each person to do the job?
so the amount of time it takes the designer to do a job is 1/1 the assisstant will do 1/17 of it in the same amount of time, right?
if the job done together is done in 6 days that means the designer did 6 parts to the assistants 6/17 parts
where did 1/17 come from?
i'm supposed to declare variables and have equations and pellet
and pellet*
its the information in the posted problem; it takes 16 more days to finish the same amount of work; D = 1 day done A = 1 + 16 days done
the ratio is 1 to 17 then; right?
its takes the assistant alone 16 more days than it would take the designer working alone..
i see, i read it wring :)
lol okay! you were confusing me for a minute!
The assistant working alone could complete the job in 16 more days than the designer working alone. D = D days A = D+16 days add them together and we get: 2D + 16 days to do 2 of the same jobs right? im thinking here
2D + 16 would be done in 12 days then ... that make sense?
D = # of days designer could do it alone A = # of days Assistant could do it alone ?
yes, it was either that or come up with something that would just confuse the situation :)
okay; so one equation would be: a=2d+16 what would the other one be?
a+d=6 ?
A+D = 6, yes if we knew what A and D where .... but all we know is what it is if they workd alone. right?
but when they work together; they can complete it in 6 days.
right, so lets assume they do 2 of the same jobs; they would finish in 12 days correct?
yea
So if D can finish in D days on one job; let her do that job alone A can finish the other job in D+16 days, so let A do the other one .... is my thinking
D + (D+16) = 12 days for 2 jobs then, and this might be more work then needed, but to me it makes sense
i'm not following
let me try to see if this is going to work first, then ill try to describe it if it does :)
haha okay.
2d + 16 = 12 days 2d+16 ------ = 1 days work ; reduce 12 d + 8 ----- = 1 days work 6 d/6 + 8/6 maybe, and i cant be sure yet, the A does the same amount of wok in 1' 1/3 the time it takes D to do it
6/8 = .75, of the work the D does .... .25 + .75 = 1, and thats done in 6 days; but how does this measure against the rest of it?
i wish this made more sense to me than a gut feeling :)
2d+16=12 : where is that coming from?
D=8 days; then A = 24 days if im gutting it right 1/8 + 1/24 = 4/24; 24/4 = 6 all right
|dw:1316129614728:dw|
spose we have 2 jobs to do in 12 days; since 6 days * 2 = 12
why not just a=d+16 though?
because to me, that tells us nothing in the outcome of things; that is just a relative measure and nothing that can be quantified with a single job. We have to set up an experiment to measure against.
in other words, that is related to just this one job and we cant determine, or at least i cant determine what to measure it against ..
we know that alone it will take 16 more days to finish alone, than it does with help. we know that D can finish it alone in ..... some time frame that is undetermined
Without being able to establish the timeframe for D how do we measure another 16 days from it?
give D and A their own workspace to measure against; 2 jobs that would have taken them 12 days to complete if worked together, and D works one, while A works the other for comparison
Job = D = 6days Job = D+16 = 6days 2Jobs = 2D+16 = 12days; reduce by 2 Job = D + 8 = 6 days; divide by 6 to see how much is done in 1 day 1/6 Job = D/6 + 8/6 = 1 day .... we are getting somewhere now
these are percentages of work done in the day; 6/D and 6/8 are the speed with which the work relative to each other, and the faster one HAS to be the Designer. 6/8 = 3/4 = .75 = 75%; leaving 25% for the Assistant
the rest of this is hard to put into words ... but im trying :)
I think you are doing a great job!!
... thnx :)
\[\frac{6}{D}:\frac{6}{8},\ D=8\] but why?
would it be the same if the length was 5 extra days? 2d+5 = 12 (2d+5)/12 = 1 12/2d = 12/5; d = 5/2 = 2.5 A = 7.5 6(1/2.5 + 1/7.5) = 3.2 ..... so it seems to be a fluke
thats the best i got fer tonite, good luck with it :)
How does this work? A=16+G; G=graphic designer and A=assistant A+G=6; so we can plug A in there (16+G)+G=6 16+2G=6 2G=-10 G=-5, hmmm I dont think we can have a neg amount of days, we could plug this in to find A A=16+(-5) A=11
I don't know, it was just a thought :)
Here: Designer working alone takes t days Assistant takes t +16 days Together they work for 6 days; \[6/t+6/(t+16)=1\] clear the denominators and combine terms: \[6(t+16) + 6t=t(t+16)\] \[t^2+4t-96=0\] \[(t+12)(t-8)=0\] t must be 8 (positive time to complete job for designer Designer takes 8 days Assistant takes 24 days Together they take 6 \[6/8+6/24=1\]
Solve the following for x, the time required for the graphic designer to complete the layout solo.\[\frac{1}{x+16}+\frac{1}{x}= \frac{1}{6}\]x=8, x+16 = 24
Join our real-time social learning platform and learn together with your friends!