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Verify the identity (1+csc 3B)/(sec 3B) - cot 3B = cos 3B
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The 3B is just a red herring \[\frac{1+csc(3B)}{sec(3B)}-cot(3B) = cos(3B)(1+\frac{1}{sin(3B)})-\frac{cos(3B)}{sin(3B)}\] \[=cos(3B)(\frac{sin(3B)}{sin(3B)} + \frac{1}{sin(3B)})-\frac{cos(3B)}{sin(3B)}\] \[=\frac{cos(3B)sin(3B) + cos(3B)}{sin(3B)} - \frac{cos(3B)}{sin(3B)}\] \[=\frac{cos(3B)sin(3B)}{sin(3B)} = cos(3B)\]
The operative identities: \[csc(x) = 1/sin(x)::sec(x) = 1/cos(x):: cot(x)=cos(x)/sin(x)\]
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