okay so with exponential functions and looking at g(x)=2^x when its negative where does the 1/2 come from
can you rephrase your question; I don't understand
Do you mean the slope?
g(x)=2^x the base of 2 is a fixed number and the x is your variable. Let's look more closely at the function g(x) = 2x. To evaluate this function, we operate as usual, picking values of x, plugging them in, and simplifying for the answers. But to evaluate 2x, we need to remember how exponents work. In particular, we need to remember that negative exponents mean "put the base on the other side of the fraction line". this is what the notes gave me
i think i understand the question
you mean when x is negative.
yes!
So, a^-n = 1/a^n, for example.
you lost me
so don't forget that \[b^{-n}=\frac{1}{b^n}\] so for example if you have \[2^x\] hten \[2^{-1}=\frac{1}{2}\] and \[2^{-2}=\frac{1}{2^2}=\frac{1}{4}\]
thats right but that doesnt make sense on why the 1 is in the front and the variable is positive
a negative number in the exponent does not make the number negative
think of powers of ten
so your saying that when the exponet is negative you have to take the recipocal of it?
\[2^x = 1/(2^-n)\]
\[10^3=1000\] \[10^2=100\] \[10^1=10\] \[10^0=1\] \[10^{-1}=0.1\] \[10^{-2}=0.01\] \[10^{-3}=0.001\] etc
Wait, sorry! \[2^x = 1/(2^-x)\]
yes the negative exponent means take the reciprocal
@razzles 2^{-n}
math is weird but not that weird. if you want the number to be negative, stick a minus sign in front
\[2^{-2}=\frac{1}{4}\] \[-2^{-2}=-\frac{1}{4}\]
Law of exponents: \[x ^{-a} = 1/ x ^{a}\]
so with the negative numbers you move the decimal one place to the left?
how are you getting 1/4 from 2^-2
yes im this slow...
got it now :D thanks guys
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