Question

find the perimeter of the triangle with the given vertices.

(-5,-2),(-1,4),(3,-1)

round your solution to two decimal places.

Answer 1

use the distance formula to find each side ...squareroot of (xsub2-xsub1)+(ysub2-ysub1)

Answer 2

(-5,-2),(-1,4),(3,-1)
5 2 5 2 5 2
------------------
0,0 4,6 8,1


(-5,-2),(-1,4),(3,-1)
1 -4 1-4 1 -4
------------------
-4,-6 0,0 4,-5


(-5,-2),(-1,4),(3,-1)
-3 1 -3 1 -3 1
-----------------
-8,1 -4,5 0,0

\[P=\sqrt{16+36}+\sqrt{64+1}+\sqrt{16+25}\]

Answer 3

i coulda stopped at twice, but i had to make sure :)

Answer 4

\[\sqrt{(-5+1)^{2}+(-2-4)^{2}} + \sqrt{(3+1)^{2}+(-1-4)^{2}} + \sqrt{(3+5)^{2}+(-1+2)^{2}}=21.6765\]

Answer 5

Also... http://www.wolframalpha.com/input/?i=perimeter+of+%28-5%2C-2%29%2C%28-1%2C4%29%2C%283%2C-1%29

Answer 6

thanks