Question

What's the second derivative of 3xe^x?

Answer 1

\[\large y = 3xe^x\]


\[\large y^{\prime} = 3e^x+3xe^x\]


\[\large y^{\prime\prime} = 3e^x+3e^x+3xe^x\]


\[\large y^{\prime\prime} = 6e^x+3xe^x\]

Answer 2

using product rule:
first derivative:
\[y^'=3x(e^x)+e^x(3)\]
second derivative:
\[y^''=[3x(e^x)+e^x(3)]+e^x(3)\]
simplify, thats your second derivative

Answer 3

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