Question

lim (x^2 - 6)/(x-8)
x->8

Answer 1

Assuming you meant (x^2 - 64)/(x-8)


lim (x^2 - 64)/(x-8)
x-> 8


lim ((x-8)(x+8))/(x-8)
x-> 8


lim (x+8)
x-> 8


8+8


16


So


lim (x^2 - 64)/(x-8) = 16
x-> 8

Answer 2

no, i meant 6 not 64...

Answer 3

if it's (x^2 - 6)/(x-8), then the limit as x--> 8 does not exist because the left and right hand limits are not equal

Answer 4

Agree with Jim
1st find lim f(x)whn x--> 8+ and then lim f(x) whn x-->8-