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Integrate tan^2 (x)
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i suggest rewriting tan^2(x) and sec^2(x)-1 and then integrating
since tan^2(x)=sec^2(x)-1 INT (tan^2(x)dx)=INT Sec^2(x)-1 since the d/dx(tanx)=sec^2(x) the intergral is nothing more than tan(x)-x+C
thanks:) i forgot about that identity lol, was trying to use sin and cos:)
oh no, sin and cos, would take you to places you do not want to got to :)
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