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Mathematics 16 Online
OpenStudy (anonymous):

What is the fractional equivalent of 0.12321232123212321...?

OpenStudy (anonymous):

112/909

OpenStudy (anonymous):

method of how you got to the answer please?

OpenStudy (anonymous):

Whenever you have a fraction like that you need the length n of the period, in this case 4. Then divide the recurrent numbers, in this case 1232, by 10^(n+1)-1. So you get \[ \frac{1232}{9999} = \frac{112}{909} \]

OpenStudy (anonymous):

Thanks.

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