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A rectangle is bounded by the x-axis and the semicircle y = √(36 – x^2). Write the area A of the rectangle as a function of x, and determine the domain of the area function.
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How can a rectangle be bounded by a straight line and a semicircle? I'm confused.
this is the image of the problem
hope this helps
oh ok.
Let (x,y) be the point on the diagram. Then the length of the rectangle is 2x and its breadth is y = sqrt(36-x^2). Thus its area f(x) is \[f(x)=2x\sqrt{36-x^2}\] Its domain would be \[x\in (-6,6)\], as otherwise the rectangle wouldn't be defined.
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Sorry its domain would be \[x \in (0,6)\] not as I stated previously.
thank you
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