what is the power dissapation for a series circuit that has 10V ,1.0 Kohms ,6.8 Kohms

Question

stormfire1 · Answer

In series current is constant and you can just add up the resistances to get 7.8 Kohms

First, find the current in the circuit using the formula E = I * R: 
10V / 7800ohms = .0013A

Now find the total power dissipated using P = I * E
P = .0013A * 7800 = 10.14W

anonymous · Answer

power dissipation is I^2 * R

anonymous · Answer

first take sqaure of 0.0013 and then multiply with 7800

stormfire1 · Answer

Oops...I put the formula down but didn't apply it right.  It should have been .0013A * 10V...which = .013W.  The I^2*R formula does the same thing.