how do I graph a line when I have the slope and only x coordinates? Ex. Slope of 8, with points (0.5,y), (1,y),(2,y),(3,y) is that even possible or am I reading the problem wrong??
(1,y ) (2,y) -1-y -1-y ----------- 0,0 1,0; you cant, unless you means each y is different
then it would be (1,f(1)) (2,f(2)) -1-f(1) -1-f(1) -------------- 0 1,f(1)-f(2) = slope, y/x f(1)-f(2) = 8
without knowing the actual function that relates x to y, there isnt a way that i can see
(1,0) (2,8) is just as valid as (1,23) (2,31)
all the y points are supposed to be different :S
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you need at least one instance of an initial condition
thats what I thought but that's all the problem gives me
(0.5,f(1)-4) (1,f(1)) (2,f(1)+8) (3,f(1)+16)
you that the slope\[= \tan \theta\]where \[\theta\] = the positive angle between the line and the x axis. here\[\tan \theta =8 \] => \[\theta =\tan^{-1} 8\] so draw a line making an angle so........... and then adjust it in such a way that he x coordinates satisfy the line
dhash, there are infinte solutions without knowing how x affects y
how can we locate a y intercept when there is no relation to associate with it?
i guess it's just my textbook being stupid again ill have to talk to my teacher
thanks both of you for trying tho
good luck :)
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