Question

what is the domain of (x^2 - 7x + 6)^(1/2)?
and how do you find the answer?

Answer 1

domain = all real

Answer 2

usually a domain is restricted when there is an x in the denominator basically domain (for what values x can create a capable solution) that's how i look at it

Answer 3

there is not squared roots or denominators, so the domain of that function are all real.

Answer 4

i'm doing my work online, so when i input an answer it immediately tells me whether the answer is right or wrong. i put (-infinity, infinity) to show "all real" but it didn't work.

Answer 5

hint: \[\Large (x^2 - 7x + 6)^{\frac{1}{2}}=\sqrt{x^2 - 7x + 6}\]

Answer 6

ahhh sorry. I didnt see the a/b exponent. Of course the answer we gave you is not correct.

Answer 7

give me one minut and I will edit the correct answer for you :)

Answer 8

thank you!

Answer 9

I got -inf to inf again. taking into account the squared root

Answer 10

well i know it's not "all real" because 2 doesn't work. it gives a negative value in the square root and so it's not real.

Answer 11

Domain is \[\Large \left(-\infty,1]\cup[6,\infty\right)\]

Answer 12

You find this by solving \[\Large x^2 - 7x + 6\ge 0\]

Answer 13

sorry. the domain is (-inf,1]U[6,inf)
drinking a little bit

Answer 14

lol emunrradtvagm

and thank you jim!

Answer 15

Remember that you cannot take the square root of a negative number


So the radicand must be nonnegative

Answer 16

yeah I hade to choose a number between 1 and 6 and I took 0. Isnt that funny? sorry for the confusion

Answer 17

i understood the concept but didn't know how to compute the domain. thanks for the answer and explanation.

Answer 18

You have to factor out what is inside of the squared root