How do I estimate the instantaneous velocity at a certain time when I am not given the function, but I am given points? Assuming that this smooth curve represents the motion of the body, estimate the velocity at t=1.0, t=2.5, and t=3.5 (t, s) = (time in seconds, s in feet) (0, 3.5); (0.5, -4); (1.0, -8.5); (1.5, -10); (2.0, -8.5); (2.5, -4); (3.0, 3.5); (3.5, 14); (4.0, 27.5)
This question isn't as difficult as you think it is. first off, you have to understand what instantaneous velocity is: Instantaneous velocity is the speed at a one point in time, or instant. That being said when you are supposed to find the instantaneous velocity at t=1.0 all you need to know is the speed at t=1.0. Lucky for you, this is given to you with the points! Your speed at 1.0=-8.5 Your speed at 2.5=-5 your speed at 3.5=14 You don't have to do any math here, you just need to understand what the question is asking you for. Does that make sense? any questions?
-8.5 is the distance (in feet) though lol; not velocity.
I read "s in feet" and assumed it was speed. is this a typo on your end, or is that how the question is written? Or is it s as in displacement...
Yes, s is displacement
usually velocity is measured in meters per second. thats the standard unit
Sorry, my book says feet...
Okay, that makes a little more sense... that's what I get for assuming. Okay, give me a second and I'll see if I can figure is out with displacement.
since 's' is displacement, i think u should divide 's' by 't' to obtain velocity
Yes, mathballet8888 is correct: think of the equation for distance: D=V/t (where D=distance V=Velocity t=time) now solve for V V=D/t
yea velocity=(displacement)/(time elapsed)
Hmm.. that's only the average velocity though. This is a even problem so I don't have the answer in the back of the book, but a very similar problem before this one has an answer in the book... and it has the notation s'(1) (for the 1 sec)... but how do I find the derivative if I do not know the function? o-o
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