find limit as X reaches infinity
5x^2 -8x-13

Question

find limit as X reaches infinity
 5x^2 -8x-13

anonymous · Answer

$\infty$.

anonymous · Answer

∞

anonymous · Answer

My infinity looks much cooler than yours kushashwa23 :P

anonymous · Answer

but if i take it's derivative and then try to find the answer, shouldn't that work?

anonymous · Answer

wait :
$$∞$$

anonymous · Answer

$$\color{red}{∞}$$

anonymous · Answer

so 4/5 should be the answer right?

anonymous · Answer

No! I think you're talking about L'Hopital's Rule, which is only applicable if you have something of the form $\frac{0}{0}$ or $\frac{\infty}{\infty}$.

anonymous · Answer

anwarA now mine is cooler one :P
$$\color{ blue}{∞}$$

anonymous · Answer

I agree, and you deserve a medal for that!

anonymous · Answer

Call me Anwar.

anonymous · Answer

ok thanks

anonymous · Answer

but if i try to plot the graph, it has a zero gradient at x=8, so the limit would be where x= 4/5

anonymous · Answer

and putting x=4/5 in the actual equation i can get the limit right?

anonymous · Answer

ans will be
$$\infty$$

anonymous · Answer

read my suggestion and let me know if my approach is wrong or not

anonymous · Answer

I don't think I get your question. See the graph here http://bit.ly/ncbWjB. You can see that the function goes to $\infty$ as you take large values of $x$.

anonymous · Answer

okay=)