find limit as X reaches infinity 5x^2 -8x-13
\(\infty\).
∞
My infinity looks much cooler than yours kushashwa23 :P
but if i take it's derivative and then try to find the answer, shouldn't that work?
wait : \[∞\]
\[\color{red}{∞}\]
so 4/5 should be the answer right?
No! I think you're talking about L'Hopital's Rule, which is only applicable if you have something of the form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\).
anwarA now mine is cooler one :P \[\color{ blue}{∞}\]
I agree, and you deserve a medal for that!
Call me Anwar.
ok thanks
but if i try to plot the graph, it has a zero gradient at x=8, so the limit would be where x= 4/5
and putting x=4/5 in the actual equation i can get the limit right?
ans will be \[\infty\]
read my suggestion and let me know if my approach is wrong or not
I don't think I get your question. See the graph here http://bit.ly/ncbWjB. You can see that the function goes to \(\infty\) as you take large values of \(x\).
okay=)
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