Question

The sum of the first and third consecutive integers is equal to twice the second. What are the Integers? Explain.

Answer 1

let the consecutive integers be x , x+1 , x+2
According to the question :
\[x+(x+2) = 2(x+1)\]
\[x+x+2=2x+2\]
\[2x+2=2x+2\]
i do think it is a logic ,,,,,,,,,,,,,,,,, all the consecutive integers accept in this case i mean :
5,6,7 : 5+7=2(6)
12=12
6,7,8 : 6+8 = 2(7) => 14=14

Answer 2

\(x+x+2=2(x+1) \implies 2(x+1)=2(x+1) \implies x=x\). That means it's applicable to any three consecutive numbers. Take for example 2,3,4 or 5,6,7.

Answer 3

You can see that \(2+4=2\times3\) and that \(5+7=2\times6\) and so on.

Answer 4

-5,-4,-3
-5+(-3) = 2(-4)
-5-3=-8
-8=-8
anwar 's answer agrees with mine too so now i am confirmed that all the integers are applicable in these situations ( consecutive )

Answer 5

WHETHER THEY ARE POSITIVE OR NEGATIVE

Answer 6

thanx

Answer 7

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