Question

a car accelerates uniformly from rest to a speed of 22.8 km/h in 8.1s
-find the distance in travels during this time
(answer i units of m)

Answer 1

22.8 km/h*(1000m/1km)*(1h/3600sec)=6.333m/sec

Answer 2

v(average)=1/2 (v(final)+v(initial)
distance=v(average)*t

Answer 3

Given initial velocity u=o m/s
final velocity v= 22.8 km/h
=6.33 m/s
Given acceleration is uniform & time as 8.1s
=> acceleration a = (v-u)/t
= 6.33/8.1
= 0.781 m/s^2
Distance travelled during this time = 1/2(at^2)
= 1/2(0.781* 8.1^2)
= 25.62m