Question

A car starts from rest and travels for 5.0 s with a uniform deceleration of 3.0 m/s^2.
-what is the final veloecity of the car(answer in m/s)
-how does the car travel in this time interval?

Answer 1

a=v(final)-v(initial) / t.
-3m/s^2=v(final)-0/5
v(final)=-15m/s
The velocity of the car decreases

Answer 2

how far does it travel in this time interval?

Answer 3

v=d/t
v*t=d
15m/s*5s=75m