Question

x+5/4x-37=78

Answer 1

x=22

Answer 2

tyy but how did you do itt

Answer 3

oops messed it up let me try again..

Answer 4

cross multiplying then solve for x

Answer 5

x+5/4x-37=78
x+4x/5-37=78
5x/-32=78
5x=78 x -32
5x=2496
x=499.2

Answer 6

yeah but raheen can you show steps plzz

Answer 7

tyy karatee

Answer 8

ur welcomeeee alanah!!

Answer 9

Is the equation \[\large \frac{x+5}{4x-37}=78\] or is it \[\large x+\frac{5}{4x-37}=78\] or is it \[\large x+\frac{5}{4x}-37=78\] or is it \[\large \frac{x+5}{4x}-37=78\] ???

Answer 10

lol what @ jim

Answer 11

so confused

Answer 12

the third one

Answer 13

there are 4 possible ways to read what you wrote and I've listed them above

Answer 14

oh ok thx

Answer 15

\[\large x+\frac{5}{4x}-37=78\]


\[\large x+\frac{5}{4x}=78+37\]


\[\large x+\frac{5}{4x}=115\]


\[\large x\left(\frac{4x}{4x}\right)+\frac{5}{4x}=115\]


\[\large \frac{4x^2}{4x}+\frac{5}{4x}=115\]


\[\large \frac{4x^2+5}{4x}=115\]


\[\large 4x^2+5=115(4x)\]


\[\large 4x^2+5=460x\]


\[\large 4x^2-460x+5=0\]


Now solve this equation using the quadratic formula to find the answers.

Answer 16

i bet alanah is as confused as i am?

Answer 17

the answer will depend on what the equation really is