Question

Please help,

log4(x-2) + 2log4(x) = 1 + log4(2x)

Thanks

Answer 1

is 4 the base?

Answer 2

yep

Answer 3

log 4 [2x(x)/(2x)] =1 ===> x=4

Answer 4

log4(x-2) + log4 (x)^2 - log4(2x) = 1
log4[ (x^2(x-2)) / 2x] = log4 4
(x^2(x-2)) / 2x] = 4
x(x-2) = 8
x^2 - 2x - 8 = 0
(x -4)(x+2) = 0
x = 4 or -2

Answer 5

-2 is not valid
x = 4

good work raheed - i did it the long way!!

Answer 6

awesome, thanks a lot i appreciate it

Answer 7

yw