Has anyone ever seen an "of" statement...here is the problem... |x| = -a + or - A
|x| = -a How can you modify the value of a so that you would have a solution to |x| = -a of +a
if x<0, then |x|=-x if x>0, then |x|=x if x=0, then |x|=0 so for example -3<0, then |-3|=-(-3)=3 for example 3>0, then |3|=3
|3| =3 whereas |-3| =-(-3) =3 , consider the absolute value notation like a device that gives a positive value all the time
lol you used 3 too
wooow , good chance
I understand the absolute value part but I dont get the of (plus or minus) the a
\[|x|=\pm x\] since we don't know if x>0 or if x<0
If |x| = a, then x = a or x = -a where 'a' is a nonnegative number
Ex: |x| = 6, so x = 6 or x = -6
you are convinced that the absolute value output would be a positive or zero, right?
absolute value is just like a distance from 0 got that part
the input can be any real number (and imaginary but lets not go there)
exactly a distance is a scalar quanitity in , phyiscally
|x| = -a of (+ or -) a...What is "OF"
might this way of writing the definition of the absolute value confused you, let it me write in another way. using a draw.
|dw:1316303451939:dw|
look at the darwing now and tray any number as an example
what's ur feedback?
Or put another way, \[\Large |x|= \begin{cases} x & \text{if } x\ge 0, \\ -x &\text{if x < 0.} \end{cases}\]
exactly
but he might see it not clear, so may talk to him about after removing the
unclearity
of the way he found the definition .
I dont think you guys are hearing me...I dont know what the "OF" in that statment means, I am now thinking its a teacher typo
yeah sounds like it should be "or"
oh, man yopu are taking about some kinda mistyping
forget about that
I am not sure lol
it doesn't matter here
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