vector calculus: u=3i+2j-4k and v=i+6j+5k, find scalars a and b so that the vector w=5i-18j-32k can be written in the form w=au+bv
set up system of equations 3a +b = 5 2a +6b = -18 -4a +5b = -32 a = 3 b= -4
Where did you get those equations from?
<5,-18,-32>=a<3,2,-4>+b<1,6,5>
3a+b=5
however i'm not sure if there is infinite solutions in this case but dumbcow has set it up right
from what outkast is doing
And what would that be?
you could use linear matrix to solve
basically i'm taking the vector components and equaling them
Why are you allowed to do that?
so if you have a<3,2,1> or <v1,v2,v3> , then the scalar of that would be <3a,2a,1a>
No, first of all, where does a and b even come into play?
yes cv = <kv1,kv2,kv3>
We were given u and v with i,j, and k components
i mean kv = and he's asking in the question what scalars a and b are
What is kv? kilovolts?
lol k is scalar
None of this is making any sense
if k is a scalar then kv=<kv1,kv2,kv3>
I don't know what that means
it means that if you times a vectors by a scalar your components will be times the scalar
<i,j,k>=<v1,v2,v3>
Vector Calc 101....In order for me to understand, you'd have to do a complete presentation of it
But that's okay. I'm going to leave and come back in five minutes. When I come back, I might understand it better than you.
yeah i'm taking the class right now, and it can be confusing at times.... so many equations
anyways dumbcows answer is correct, does not have infinite solutions however i wouldn't know how to explain it without using what i've learned in MAT2880
it tally makes sense, its just multiplying each vectors by its corresponding one. By the way dumcows, wasnet there a shortcut by cross multiplication? or am i confusing that for are of parallelogram
shortcut? i dont know maybe, i am not aware of one you could also set up a matrix and solve using reduced row echelon form
Thank you dumbcow....thats what i did also but i got stuck when i realized i have 3 eqns nd 2 unknowns
Understanding this from a geometrical standpoint is very helpful
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