Question

need help with the attachment

Answer 1

a) Just plug in 1 for the numerator and g(x) for the denominator in the quotient rule.
b) \[ -{\frac {1+k{{\rm e}^{s}}}{ \left( s+k{{\rm e}^{s}} \right) ^{2}}} \] assuming y is a function of s.
c) Follows from \[ x^{-n} = \frac{1}{x^n} \] and \[ \frac{d}{dx} x^n = nx^{n-1} \]

Answer 2

is the quotient rule the same thing as the reciprocal part b?

Answer 3

What do you mean? The reciprocal rule is a special case of the quotient rule. You can use either one for part b, but it's easier to use the reciprocal rule.

Answer 4

The quotient rule f'g-fg'/g^(2)

Answer 5

but g(x) is just a variable

Answer 6

ok I got it

Answer 7

What is your question? g is not just a variable, it's a function.

Answer 8

Ok, hit good answer.

Answer 9

OK I need help with differentiating the bottom on part could you show me step by step how to differentiate that one?

Answer 10

part b

Answer 11

and also the numerator of the function

Answer 12

You need to differentiate\[ \Large s+k\cdot e^s \] with respect to s.

Answer 13

The derivative of a sum is the sum of derivatives, so differentiate s and then differentiate k*e^s.

Answer 14

What is the derivative of s?

Answer 15

1

Answer 16

Yes. And what is the derivative of e^s ?

Answer 17

@ta, see the attachee

Answer 18

e^(s)

Answer 19

Your attachment doesn't include part b) explanation, thats what he asked about.

Answer 20

Yes, so now you can add them together and you get the derivative

Answer 21

And then just plug that into the formula in part a)

Answer 22

1+e^(s)

Answer 23

No! Don't forget the factor k!

Answer 24

k does not depend on s, so you can just leave it unchanged

Answer 25

But you must not forget it :D

Answer 26

here u r

Answer 27

raheen there is still no explanation of part b :D

Answer 28

been answered all

Answer 29

part b asking to find using the rule only

Answer 30

ta123 do you have more questions?

Answer 31

whears the other 2 parts are to prove

Answer 32

@ta got that?

Answer 33

lol raheen are you just trying to get a medal, because I can give you one if thats what you want :D

Answer 34

your answer is wrong raheen, I got -1-ke^(s)/(s+ke^(s))^2

Answer 35

no YThe, I always try to help , pls don read the things in wrong way

Answer 36

Your answer is correct ta.

Answer 37

yes, thanks for the help Y and raheen

Answer 38

ta why some ppl are using an offensive words?

Answer 39

I think I stayed with u b4 more than 2 hrs, without any annyance, right?

Answer 40

yes

Answer 41

thank u.

Answer 42

no prob!