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Write the equation in a standard form ax^2+bx+c=0 , then give the values of a,b, and c. (x+3/2)^2 = 1/4
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\[\large{x^2+3x+\frac{9}{4}}=\large{\frac{1}{4}}\]\[\large{x^2+3x+2}=\large{0}\]
\[\large{a}=\large{1}\]
b=3 , c=2
x^2+3x+2=0
how did u get this? x^2+3x+2=0
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\[(x+\frac{3}{2})(x+\frac{3}{2})= \large{x^2+\frac{3}{2}x+\frac{3}{2}x+\frac{9}{4}}\]
ok.. how about the values?
\[\large{x^2+\frac{3}{2}x+\frac{3}{2}x+\frac{9}{4}}=\frac{1}{4}\]
\[\large{x^2+3x+\frac{9}{4}}=\frac{1}{4}\]
\[\large{x^2+3x+\frac{9}{4}-\frac{1}{4}=0}\]
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\[\large{x^2+3x+\frac{8}{4}=0}\]
\[\large{x^2+3x+2}=0\]
ok ... i got it.. thanks
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