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Mathematics 8 Online
OpenStudy (anonymous):

http://www.caddomillsisd.org/100820818134650763/lib/100820818134650763/chap06.pdf I need help page 383 number 5 and 6 ,thank you

OpenStudy (anonymous):

any way I need 5, don't need 6

OpenStudy (anonymous):

For number 5, the phase shift is 3. To determine the phase shift, take the argument of the trig function and factor out the coefficient of the angle:\[\frac{\pi}{6}\theta - \frac{\pi}{2} = \frac{\pi}{6}\theta - \frac{3\pi}{6} = \frac{\pi}{6}\left(\theta - 3\right)\]You can see that the phase will be shifted horizontally by 3 units.

OpenStudy (anonymous):

I don't get

OpenStudy (anonymous):

I got it now,ty

OpenStudy (anonymous):

By rewriting the argument of the trig function this way, you can look at it and see that whatever angle you supply as theta, it will immediately be reduced by 3 before any other calculations are performed.

OpenStudy (anonymous):

I know it now you are factor

OpenStudy (anonymous):

can you help more?

OpenStudy (anonymous):

No I actually have to go to bed; work in the morning :/

OpenStudy (anonymous):

ty

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