http://www.caddomillsisd.org/100820818134650763/lib/100820818134650763/chap06.pdf I need help page 383 number 5 and 6 ,thank you
any way I need 5, don't need 6
For number 5, the phase shift is 3. To determine the phase shift, take the argument of the trig function and factor out the coefficient of the angle:\[\frac{\pi}{6}\theta - \frac{\pi}{2} = \frac{\pi}{6}\theta - \frac{3\pi}{6} = \frac{\pi}{6}\left(\theta - 3\right)\]You can see that the phase will be shifted horizontally by 3 units.
I don't get
I got it now,ty
By rewriting the argument of the trig function this way, you can look at it and see that whatever angle you supply as theta, it will immediately be reduced by 3 before any other calculations are performed.
I know it now you are factor
can you help more?
No I actually have to go to bed; work in the morning :/
ty
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