Question

Find X^2 + y^2=1 intersection with y=x

Answer 1

+- (cos(45),sin(45))

Answer 2

ohh so did good

Answer 3

yes

Answer 4

yea but i have to show how i got it.. so i subtitute
x^2+(x)^2=1 and solve and i got the answer for x
then i did the same thing for y

Answer 5

Pssh....that was easy

Answer 6

you could do it that way
but amistre was showing you how to get the answer graphically/geometrically

Answer 7

yea,,, i agree.. but i want to check if what i did after the graph was ok

Answer 8

\[x^2+x^2=1 =>2x^2=1=> x^2=\frac{1}{2} => x=\pm \sqrt{\frac{1}{2}} =\pm \frac{\sqrt{2}}{2}\]

Answer 9

yeaaaa:)

Answer 10

I was just about to do that myininaya is too quick

Answer 11

\[x=y => y=x=\pm \frac{\sqrt{2}}{2}\]

Answer 12

i have to do it both way,,, so yea that was my answer...

Answer 13

\[(\frac{\sqrt{2}}{2},\frac{\sqrt{2}}{2}) or (-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2})\]