Question

Please help me simplify
\[\frac{\sqrt[3]{24u^4}}{\sqrt[3]{3u}}\]

Answer 1

\[^3\sqrt{8u^3} = 2u\]

Answer 2

So you just divide normally, then cube root it. I was making it more difficult than it was lol
I saw a radical in the denominator and automatically assumed you had to cube both the numerator and denominator to simplify the expression.

Answer 3

\[(24u ^{4}/3u )^{1/3}\]