find the range of a function.....a)f(x)=10-x^2
b) (x^2)/(1-x^2)=f(x)

Question

anonymous · Answer

a) is a parabola that opens downward with vertex (0, 10), so the range is from negative infinity up to the vertex$$(-\infty, 10]$$

anonymous · Answer

what is a pabola?

anonymous · Answer

b) this rational function has a horizontal asymptote y=-1, so the range is all real numbers except -1:$$(-\infty,-1) \cup (-1, \infty)$$

anonymous · Answer

parabola?*

anonymous · Answer

when you have polynomial function with x^2 it has the shape called a parabola; i will attach a sketch

anonymous · Answer

to find range you really have to know something about the graph of the function

anonymous · Answer

but isnt 10-x^2 a binomial?...im confused sry

anonymous · Answer

yes, why does that concern you?

anonymous · Answer

b.c you said its a polynomial lol

anonymous · Answer

parabolas come from functions that look like$$y=ax^2+bx+c$$where a can't equal zero, but b or c can equal zero; in your case b=0

anonymous · Answer

yes, why does that concern you?

anonymous · Answer

ohhh ok i get it thanks soo much!! =]