Question

log_a(9) / 2log_a(27)

Answer 1

ans it plzzzzzzzzzzzzzzzzzzzzzzzzzzz

Answer 2

maybe use the change of base formula

Answer 3

plz write how to do

Answer 4

= loga9 / loga9^3
- i assume u want to simplify??

Answer 5

yeah simplify

Answer 6

the thing thats bothersome is the 2 in front of the log_a27

Answer 7

i think thats what it is

Answer 8

let y = loga 9
9 = a^y
z = loga729 = loga 9^3

log a^9 / loga^9^3
= 1/3
thats it 1/3

Answer 9

@jimmy- yea thats what i got too. if u simplify log9/2log27, i got .3333333 aka 1/3

Answer 10

right

Answer 11

log_a(9)/2log_a(27)
= log_a(3^2) / 2log_a(3^3)
= 2 log_a(3) / 6 log_a(3) - Using the power identity
= 2/6 = 1/3
Read Wikipedia: http://en.wikipedia.org/wiki/Logarithms#Product.2C_quotient.2C_power.2C_and_root