what is the 35th term of an arithmetic sequence where a1=-7 and a18 = 95
using the formula for an arith seq: an = a1 + d(n-1) , and the given information we can do this. a18 = -7 +d(18-1) 95 = -7 +d(17) 102 = d(17) 102/17 = d in this case,
a35 = -7 +(102/17)(35-1) = 197
102/17 reduce to 6 if you wanna make it easier :)
Thank you!
youre welcome
Wait what if the 1 is lowered down along with the 18...
not to the power of but lowered in the equation if you know what i am talking about
termed, yes; then a35 becomes a34 and the term that was a36 becomes a35
so either evaluate the term at a36, or take a35 and add to it
add 6 to it since that is the common difference between terms
197 + 6 = 203 a36 = -7 +6(35) = 203 does that make sense?
yes, well i think so. could you help me with one more to make sure i have it?
i can try :)
thanks :). okay the 27th term of an arithmetic sequence where a(termed 1) =38 and a(termed 17) =-74
you type out the process as best you can and let me see how your doing
start out with: an = a1 + d(n-1) ; and solve for d
Ok wait so I used this equation right?
or we can solve for d abstractly and then fill in the parts :) an - a1 ------ = d n-1 a17 - 38 -------- = d 17-1 -74 - 38 -------- = d 16 -112 -------- = d = -56/8 = -7 16
its the standard equation for an arith seq, so yes
Wait the choices i have though are -144, -20.5, -151, and -22.75
then i suggest we go thru to the end of the solution instead of stopping halfway at -7
d = -7 is not the same as a27
an = a1+ d(n-1) a27 = 38 -7(27-1) = 38 -7(26) = 38 -182 = -144
So thatcomes to be -144?
as long as i did the math in me head right .... yes
Thank you so much!!!!! I get most of them now. Thank you.
good luck :)
thanks :)
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