Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Ten people, 6 boys and 4 girls are playing on the playground. Miss Tweedle selects a group of 5 at random. What is the probability that the group has 3 boys and 2 girls?

OpenStudy (amistre64):

C(5,3) .6^3 .4^2 maybe?

OpenStudy (anonymous):

do i multiply.......?

OpenStudy (amistre64):

.3456 if i did it right :)

OpenStudy (amistre64):

its a binomial distribution; b=.6 and g=.4 bbbbb bbbbg bbbgb bbgbb bgbbb gbbbb bbbgg bbgbg bgbbg gbbbg bbggb bgbgb gbbgb etc

OpenStudy (anonymous):

ohhh so is there any formula for this? like nCr?

OpenStudy (amistre64):

yes

OpenStudy (amistre64):

C(n,r) tends to be a simpler way to express it

OpenStudy (anonymous):

soo its 6C3 and 4C2?

OpenStudy (amistre64):

5 pick 3 boys = C(5,3) b^3 g^2

OpenStudy (anonymous):

5C3, 5C2, 6C3, 4C2 ?

OpenStudy (amistre64):

not quite .... its a binomial distribution

OpenStudy (amistre64):

6/10 * 5/9* 4/8 * 4/7 * 3/6 is more like it

OpenStudy (anonymous):

ohh thankyou, so after i solve all of that, what do i do?

OpenStudy (anonymous):

Not quite, that's assuming you pick three boys in row, followed by two girls

OpenStudy (amistre64):

you multiply it by the number of ways there are to pick that

OpenStudy (amistre64):

5C3 ways to do so

OpenStudy (anonymous):

4/10 * 3/9 * 6/8 * 5/7 * 4/6, two girls followed by three boys, slightly different probability

OpenStudy (anonymous):

so i do 5C3 then 5C2?

OpenStudy (amistre64):

bbbgg bbgbg bgbbg gbbbg bbggb bgbgb gbbgb bggbb gbgbb ggbbb 10 ways

OpenStudy (anonymous):

"4/10 * 3/9 * 6/8 * 5/7 * 4/6, two girls followed by three boys, slightly different probability" -so do i do that and add them?

OpenStudy (amistre64):

so to recap; the P(b & b & b & g & g) = \(\cfrac{6.5.4.4.3}{10.9.8.7.6}\) and there are 10 ways to pick that so \(\cfrac{\cancel{10}.\cancel{6}.5.\cancel{4}.\cancel{4}2.\cancel{3}}{\cancel{10}.\cancel{9}3.\cancel{8}\cancel{2}.7.\cancel{6}}\)=\(\cfrac{10}{21}\)

OpenStudy (amistre64):

that is such a pain to type :)

OpenStudy (anonymous):

oh im sorry :(

OpenStudy (anonymous):

10*9*8*7*6 comes from the 5 group i get that 6,5,4 for boys and 4,3 for girls...

OpenStudy (anonymous):

ohh i get it :D thankyou!!!

OpenStudy (anonymous):

That makes sense. I wouldn't call it a binomial distribution though, because the probability of picking a boy or girl is not constant (i.e., no independence between trials).

OpenStudy (amistre64):

yay!! :)

OpenStudy (amistre64):

yeah, i saw that it wasnt binomial after i started decresing the boy girl count lol

OpenStudy (anonymous):

thankyou so so so so much :) biggest help i've ever gotten today :)

OpenStudy (amistre64):

binomial-ish at best ;)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!